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Quick Text For Problem List with Description Only NO CODE

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Last Post by Sirna 9 years ago

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Sirna

(@sirna)

Posts: 384

Honorable Member

Topic starter

I currently have a quick text in place to drop in the Problem list anywhere within an office note/Form/Text View. We are looking for this quick text to only show the Problem Naming Convention and omitting the ICD-10 code from the list. Current Quick Text is:

.prob: {PROB_AFTER("list")}

.probnew: {PROB_NEW("List")}

Please advise if anyone has a solution to just display the Problem List with names only and no codes.

Thank you,

Sirna

Posted : September 14, 2015 4:31 am

aroberts

(@aroberts)

Posts: 176

Reputable Member

You will need to delimite the list- I can't remember if the help guide in CPS breaks this down for you or not-- I am sure someone else on the forum has delimted this already and will post

Posted : September 14, 2015 4:46 am

aroberts

(@aroberts)

Posts: 176

Reputable Member

Yes- it is broken down for you in the help area of CPS:

Fields returned by PROB_AFTER("delimited"): problem type, problem code (ICD-9), problem comment, onset date, stop date, stop reason, problem code (ICD-10), problem identifier (PRID), last modified date.

Hope that helps- Amy

Posted : September 14, 2015 4:52 am

Adam Daniel

(@adaniel)

Posts: 524

Prominent Member

This in a data display, dropdown, etc works:

{!fn fnProbFormat() {

local hold = getfield(PROB_AFTER("delimited"), "|", "")
local temp
local rslt = ""

for i = 1, i <= size(hold), i = i + 1 do
temp = getfield(hold[i], "^", "")
if (rslt <> "") then
rslt = rslt
endif
rslt = rslt + temp[2] + "
"
endfor

return rslt
}}

But i've never had luck with it in quicktext. If you find the answer please post.

Posted : September 14, 2015 5:10 am

joeg1962

(@joeg1962)

Posts: 843

Noble Member

I created a quicktext --> .probtext

Defined as -->

{global prbl = getfield(PROB_AFTER("list"),"\r","")
global probsize = size(prbl)
global probicd = ""
for cnt = 1, cnt < probsize, cnt = cnt + 1
do
icddlm =match(prbl[cnt],"(")
if icddlm > 0 then
prb_d = sub(prbl[cnt],1,icddlm - 2)
probicd = probicd + prb_d
endif
endfor
probicd
}

Posted : September 14, 2015 5:33 am

Sirna

(@sirna)

Posts: 384

Honorable Member

Topic starter

@joeg1962 This is PERFECT!! Thank you very much!!!!!

Posted : September 14, 2015 8:28 am

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