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converting mmddyyyy to yyyymmdd to use mel sort function

MEL, SQL, Oracle

Last Post by Anonymous 1 second ago

5 Posts

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dmoroz

(@dmoroz)

Posts: 24

Eminent Member

Topic starter

Hello all,

Does anyone have a function or mel code snippet that converts a date into yymmdd format?

Thanks

Posted : December 13, 2016 3:55 am

chaddix

(@chaddix)

Posts: 177

Estimable Member

The function below could help you out...I set it up so that it can be expanded over time if you wanted different formats. Disclaimer: Untested, could crash or cause issue.

fn convertDate(d, f) { /* Incoming Parameters: d: A date, formatted as 01/01/2000 f: How you want your output string to be formatted

Example: convertDate(._TODAYSDATE, "yyyymmdd")
Returns: 20161213
*/

local retStr = ""
local dateArray

cond
case d == "": /*Do Nothing*/
case match(d, 1, "/") <= 0: /*Do Nothing*/
else:
dateArray = getfield(d, "/", "")
if size(dateArray) == 3 then
cond
case f == "yyyymmdd": retStr = dateArray[3] + dateArray[1] + dateArray[2]
endcond
endif
endcond

return retStr
}

Posted : December 13, 2016 4:14 am

dmoroz

(@dmoroz)

Posts: 24

Eminent Member

Topic starter

That works perfectly!

Thank you very much!

Posted : December 13, 2016 7:47 am

dmoroz

(@dmoroz)

Posts: 24

Eminent Member

Topic starter

May I ask if you had a way of converting it back into dd/mm/yyyy format?

I was looking at modifying your logic to do it, however I am stuck at the match, when converting from dd/mm/yyyy to yyyymmdd you used the "/" as the deliminator, what would you use for converting it back?

I played around withmaking it a string and adding a deliminator character, however then the mel sort function wont work with it.

Thanks again

Posted : December 13, 2016 9:20 am

chaddix

(@chaddix)

Posts: 177

Estimable Member

RE: Changing it back...

We could use a different function to do that, one that assumes an 8 character string always formatted as YYYYMMDD. In that case, we could do something like below (disclaimer: untested).

fn convertStringToDate(d, f) { /* Incoming Parameters: d: A date, formatted as YYYYMMDD f: How you want your output string to be formatted

Example: convertDate(20161213, "mm/dd/yyyy")
Returns: 12/13/2016
*/

local retStr = ""

cond
case d == "": /*Do Nothing*/
case size(d) == 8:
cond
case f == "mm/dd/yyyy": retStr = sub(d, 5, 2) + "/" + sub(d, 7, 2) + "/" + sub(d, 1, 4)
endcond
endcond

return retStr
}

Posted : December 13, 2016 10:12 am

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