Welcome to the NEW CHUG— your ultimate destination for cutting-edge insights and discussions at the intersection of healthcare and technology.

Our platform is dedicated to exploring the dynamic landscape of healthcare technology, empowering professionals, enthusiasts, and innovators alike with the knowledge and resources to navigate the rapidly evolving field.

From telemedicine revolutionizing patient care to the transformative potential of artificial intelligence in diagnostics, we delve into a myriad of topics shaping the future of healthcare delivery. Whether you’re a seasoned healthcare IT professional, an aspiring entrepreneur in the digital health space, or simply curious about the latest innovations, our curated content, expert interviews, and thought-provoking articles provide a comprehensive exploration of healthcare technology’s most pressing issues.

Join us as we navigate the forefront of innovation, driving forward the transformation of healthcare for a healthier, more connected world.

Have questions or suggestions? Please use the contact button below.

Notifications

Clear all

counting check boxes

Trading Post

Last Post by Anonymous 1 second ago

4 Posts

3 Users

0 Reactions

140 Views

RSS

BrandonFluitt

(@brandonfluitt)

Posts: 22

Eminent Member

Topic starter

Good afternoon everyone,

I could really use some help and I’m sure for most of you this is a simple piece of coding.

Basically, I want a count of 1 for every check box that is not blank and the total added together that I'm going to put in a data display. The closest I’ve come this morning is below and it only works if none of the check boxes are left blank. I’m sure there is a much easier – and right – way to do it.

Any help is, as always, greatly appreciated.

{fn count(a, b, c, d) {

local e = 0

local f = 0

local g = 0

local h = 0

if a <> "" then

e = 1

if b <> "" then

f = 1

if c <> "" then

g = 1

if d <> "" then

h= 1

endif endif endif endif

return (e + f + g + h)

}}

Posted : December 3, 2012 5:03 am

gibsonmi

(@gibsonmi)

Posts: 827

Prominent Member

The problem you had is if a is blank then the function exits the 'if' statement. Do it like below and it should work for you

{fn count(a, b, c, d) {

local e = 0

local f = 0

local g = 0

local h = 0

if a <> "" then

e = 1

endif

if b <> "" then

f = 1

endif

if c <> "" then

g = 1

endif

if d <> "" then

h= 1

endif

return (e + f + g + h)

}}

Posted : December 3, 2012 5:49 am

BrandonFluitt

(@brandonfluitt)

Posts: 22

Eminent Member

Topic starter

That worked perfectly.

Thanks for your help!

Posted : December 3, 2012 5:55 am

Anonymous

(@Anonymous)

Posts: 0

New Member Guest

simpler, less redundant use of local variables:

fn count(a,b){

local total = 0

if(a<>0)then

total = total +1

endif

if(b<>0)then

total = total + 1

endif

return total

}

Posted : January 2, 2013 3:56 am

Share:

24 Forums
9,940 Topics
39.9 K Posts
1 Online
6,470 Members

Forum Icons: Forum contains no unread posts Forum contains unread posts

Topic Icons: Not Replied Replied Active Hot Sticky Unapproved Solved Private Closed

Powered by wpForo Powered by wpForo version 2.4.0